Factoring $x^3 + bx^2 + cx + d$
Posted: Sat Apr 16, 2011 11:51 am
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When we factor,
where does one of the (x+6)'s go?
The (x+6) was factored out because it was common to both terms. Let's make a substitution, lets say
Then we have,
Since the y was multiplying both terms we were able to factor it out. But remember y = (x+6). So lets just plug that back in to get,
When we factor,
where does one of the (x+6)'s go?
The (x+6) was factored out because it was common to both terms. Let's make a substitution, lets say
Then we have,
Since the y was multiplying both terms we were able to factor it out. But remember y = (x+6). So lets just plug that back in to get,